Friday, 12 February 2016

Friday, February 12, 2016


Next week we will celebrate the French Canadian tradition of Le Carnaval d'Hiver.  Events run from Tuesday to Friday, and all students are encouraged to participate.  Here are the highlights:
TUESDAY: Pyjama day
WEDNESDAY: Tuque et Mitaines Day
THURSDAY: Ceinture Flechee Day (any scarf around the waist will do)
FRIDAY: Rouge et Blanc Day (hmmm...my Sens jersey is red and white...)


KUDOS TO: Kimia, for catching up so effectively from her absence.  Well done! Your learning skills rock!

POETRY CLUB: we will meet this coming Wednesday.  Bring the poems you wrote two weeks ago as we will start by a little read-aloud.  If you could also come to the club with a magazine or a newspaper, that would be poetic. 

SKI FORMS: I am still awaiting 3 from 8L.  They are due Tuesday.

8

ENGLISH
1. Essay framework 1, done.  Now, we move on to #2.  Paragraph A for "What is the role of Family in Jonas' community?" is due Tuesday.  This time, you will hand in an actual paragraph - rather than in point form.  We need to practise...


MATH
1. Unit test (2.1 - 2.3) on Tuesday.  Part 1 will be first thing in the morning, so be on time.  Part 2 (oh yes, there are two parts) will take place during English class in the afternoon.  At least you'll be comfortable writing the test in your pyjamas.   Here is the solution to question 11 in the textbook: "On a map, the distance between two cities is 5.6cm.  The scale on the map is 1:3 000 000.  A cyclist travels this distance in 4h.  What is the cyclist's average speed?"

To begin, you have to determine the units for "average speed", which is most typically in km/h.  And since the term "4h" is used in the question, we will need to convert the other units to km.  Looking at the map, the distance between the two cities is 5.6cm (D), so converted to km, that will become 0.000056km (divide by 100 000).  It's a bit strange to think of a line on a map drawn in kilometres, but you need to do this conversion.  

Next: D   :  R ::   D   :    R
        1:3 000 000:: 0.000056:x    The scale is the first D:R, and 0.000056 is "D" because that is the length of the drawing, and the "R" is our unknown - the actual distance the cyclist traveled.

Express as fractions

1/3 000 000 = 0.000056/x

Cross multiply, and you will get x = 168.  Therefore, the cyclist traveled 168km in four hours.  But the question is asking his average speed (which is a measurement of how many km traveled PER hour).

1: x :: 4:168.  (1 hour is to x km, as 4 hours is to 168 km).
Cross multiply, and you will get he travels an average speed of 42km/h

Hope that helps!

7

ENGLISH
Essay writing all week next week.  Bring your "A" game: this means plenty of rest and full attention.


MATH
1. Unit test (2.1 - 2.3) on Tuesday.  Part 1 will take place on Tuesday, and Part 2 will take place on Wednesday.

No comments:

Post a Comment